The blogs were challenging because I couldn't comment on anyone's blog who didn't use blogger, and very few people in the class use it. The blogs were helpful because they were different, and shook things up so it wasn't the same thing over and over again. Having to write about math instead of just solving a problem caused me to think about it in a whole new way. I needed to have a complete understanding of the concept I was talking about. This wasn't my first time making a video for a class, but I am definitely not a pro. My group couldn't figure out how to get the video to rotate, so we posted it sideways, but other than that, the YouTube video went pretty well. This was the first time I took part of a course online, and it went pretty ok. It made the class a little more interesting, but next year, I would have everyone use the same blog website so there are fewer problems with commenting. I did enjoy looking at other people's pages, but I didn...
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Math in the Real World
I pulled these two problems from shelovesmath.com Problem 1: To solve this problem, you need to use the differential equation: (dT/dt)=k(T-60) where t is in minutes and T is temperature in degrees. You must solve this equations first for T by isolating it on one side of the equation. (dT/dt)=k(T-60) → (dT/T-60)=kdr → ഽ(dT/T-60)=ഽkdt → ln|T-60|=kt+C → e ^(ln|T-60|)= e ^(kt)+C → |T-60|=C e^ (kt) → T=C e^ (kt)+60 → Initial Condition: (0,100), 100=C e ^(0•k)+60 → C=40, T=40 e^ (kt)+60 . So if the temperature is 80° after 10 minutes: 80=40 e ^(k•10)+60 → e ^(k•10)=ln(5) → k=(ln(5)/10) → k≈ -.0693147 . Now we can find the time it takes to cool to 70°, so plug 70 in for T and -.0693147 for k in T=40 e^ (kt)+60. 70=40 e ^(-.0693147t)+60 → e ^(-.0693147t)=(1/4) → -.0693147t=ln(.25) → t=(ln(.25)/-.0693147) → t≈ 20 minutes to cool to 70° . I chose this problem because it wasn't too complicated and it deals with things that most people deal with everyday, hot drinks, and ...
My name is Grace Brennan. I live in Wilbraham. I play softball at Minnechaug and occasionally on club teams too. I work at Greathorse. I play rec ball in the winter #Shockem I have an older brother and a younger brother. I also have a dog named Pepper. I am taking this class because I want to be prepared for math courses in college. I hope I can expand on what I learned in pre-calc, and get a better understanding of calculus in general.